16=7x^2-24x

Solution for 16=7x^2-24x equation:

16=7x^2-24x

We move all terms to the left:

16-(7x^2-24x)=0

We get rid of parentheses

-7x^2+24x+16=0

a = -7; b = 24; c = +16;
Δ = b2-4ac
Δ = 242-4·(-7)·16
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-32}{2*-7}=\frac{-56}{-14}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+32}{2*-7}=\frac{8}{-14}
=-4/7
$